Question

A side of a square is of length
8.cm. What is the lorrgth of its
diagonale​

Answer 1

Answer:

$digonal \: of \: square = \sqrt{ {8}^{2} + { {8}^{2} } }$

$= \sqrt{64 + 64}$

$= \sqrt{128}$

$11.31$

Answer 2

In △ABD

AB2+AD2=BD282+82=BD22×82=BD2BD=82

∴ Length of diagonal=82