Question

a side of a square with area 9x²-6x +1 is​

Answer 1

Answer:

3x-1

Step-by-step explanation:

side of square with area is 9x^2-6x+1

by factorising we can get its one side

9x^2-6x+1

9x^2+(-3x-3x)+1

9x^2-3x-3x+1

3x(3x-1) -1(3x-1)

(3x-1)(3x-1)

or, (3x-1) ^2

Answer 2

Answer:

$area \: of \: square \: = \: {side}^{2}$

$9 {x}^{2} - 6x + 1 = {side}^{2}$

$9 {x}^{2} - 3x - 3x + 1 = {side}^{2}$

$3x(3x - 1) - 1(3x - 1) = {side}^{2}$

$(3x - 1)(3x - 1) = {side}^{2}$

${(3x - 1)}^{2} = {side}^{2}$

$side \: = (3x - 1)$

OR

$area \: = {side}^{2}$

$9 {x}^{2} - 6x + 1 = {side}^{2}$

${(3x)}^{2} - 2(3x)(1) + (1) = {side}^{2}$

$identity \: used = {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2}$

${(3x - 1)}^{2} = {side}^{2}$

$side \: = (3x - 1)$