Question

A side of an isoceles right angled triangle is 7cm. Find its hypotenuse ​

Answer 1

Answer:

9.90 cm or 7√2

Step-by-step explanation:

As given above, we could know the hypotenuse

Let the isosceles right angled triangle be triangle ABC

AB = 7cm

BC = 7cm

AC = x cm

By Pythagoras theorem:-

AC² = AB²+BC²

So, x² = 7²+7²

x² = 49 + 49

x² = 98 cm

x = √98 cm

x = Approx (9.90 cm) or 7√2

Hence proved

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Answer 2

Answer:

H=7√2 cm

Step-by-step explanation:

in isosceles triangle Perpendicular and base lengths are equal and angle between them are 90°.

So, here  P=B=7cm

by Pythagoras  theorem

H²=P²+B²

H=$\sqrt{P^{2}+B^{2]}$

H=$\sqrt{ 7x^{2} +7x^{2}}$

H=$\sqrt{2*7^{2} }$

H=7√2 cm

Short trick

in right angled isoceles triangle of P=B=a

then H=a√2