a side of an isosceles right angled traingle is X. Find the hypotenuse. class 10 TH
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Step-by-step explanation:
the hypotense will be √2x as
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Let ∆PQR be the given right-angled isosceles triangle.
PQ = QR = x. In ∆PQR, ∠Q = 90° [Pythagoras theorem]
∴ PR2 = PQ2 + QR2 = x2 + x2 = 2x2
∴ PR = 2x2−−−√2x2 [Taking square root of both sides] = x2–√2 units
∴ The hypotenuse of the right-angled isosceles triangle is x2–√2 units.
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