Question

a side of an isosceles right angled triangle is 7cm . find its hypotenuse.​

Answer 1

Step-by-step explanation:

As given above, we could know the hypotenuse

Let the isosceles right angled triangle be triangle ABC

AB = 7cm

BC = 7cm

AC = x cm

By Pythagoras thereom:-

AC² = AB²+BC²

So, x² = 7²+7²

x² = 49 + 49

x² = 98 cm

x = √98 cm

x = Approx (9.90 cm) or 7√2

Hence proved

Therefore our answer is 9.90 cm or 7√2

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Answer 2

Given:

The side of an isosceles right-angled triangle = 7cm

To Find:

The hypotenuse of the isosceles right-angled triangle.

Solution:

Let the triangle be ABC. As we know two sides of the isosceles triangle are equal so we assume that,

   AB = 7cm

   BC = 7cm

   AC = x

Now, using the Pythagoras theorem,

AC² = AB² + BC²

x² = (7)² + (7)²

x² = 49 + 49

x² = 98cm

x = √98cm

x = 7√2 cm

x = 9.90cm

Therefore, the hypotenuse of the isosceles right-angled triangle = 7√2cm or 9.90cm.