Question

A side of an isosceles right angled triangle is x. find its hypotenuse.
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Answer 1

Answer:

according to the question:-

Pythagoras theorem is

H² = P²+ B²

In question ,

P = x and B = x

H² = x²+x²

H²= 2x²

H = √2x

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Answer 2

Answer below:

$\sqrt{2x^{2} }$

Explanation:

Given, the common side is x.

So, hypotenuse = $\sqrt{x^{2}+x^{2} }$

                           = $\sqrt{2x^{2} }$

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