a side of an isosceles right angled triangle is x find its hypotenus
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Since it's an isocles rt angled triangle, the length of the legs wide be x
I.e consider a triangle ABC with hypotenuse AC
Then
AB^2 + BC^2 = AC^2
AC=√x^2 + x^2. ( AB= BC=x)
AC=√2x^2
= x√2
The length of the hypotenuse is x√2..
Hope this was helpful..pls mark me brainliest.thank u
I.e consider a triangle ABC with hypotenuse AC
Then
AB^2 + BC^2 = AC^2
AC=√x^2 + x^2. ( AB= BC=x)
AC=√2x^2
= x√2
The length of the hypotenuse is x√2..
Hope this was helpful..pls mark me brainliest.thank u
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