Question

a side of an isosceles right angled triangle is X find its hypotenuse​

Answer 1

Answer:

$we \: know \: that \:$

$the \:two \: sides \: of \: any\: isoceles \: triangle \: are \: equal$

$let \: the \: hypotenuse \: be \: h$

$then \: according \: to \: pythagorus \: theorem$

${h} = \sqrt{ {x}^{2} + {x}^{2} } given \: one \: side \: is \: x \:$

${.}^{.} . \: h \: = \sqrt{2 {x}^{2} } = x \sqrt{2}$

Step-by-step explanation:

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