Question

A side of an isosceles right angled triangle is x.find its hypotenuse ?

Answer 1

Its √2*x by applying phythogras we can achieve this

Answer 2

Answer:

The hypotenuse is $2\sqrt x}$

Step-by-step explanation:

Let ABC be an isosceles right angled triangle with AB = x.

Since, the triangle is right isosceles, hence, two sides are equal.

AB = BC =x

Now, we apply Pythagorean theorem, to find the hypotenuse AC.

$AC=\sqrt{AB^2+BC^2}\\\\AC=\sqrt{x^2+x^2}\\\\AC=\sqrt{2x^2}\\\\AC=2\sqrt x}$

Thus, the hypotenuse is $2\sqrt x}$