Question

a side of square with area ( 4x^2 + 12x + 9 ) square unit is ...

Answer 1

Step-by-step explanation:

4x² + 12x + 9

=> ( 2x )² + 2( 2x × 3 ) + 3²

=> ( 2x + 3 )²

=> Area of square = ( 2x + 3 )²

=> side² = ( 2x + 3 )²

=> side = 2x + 3 units

Answer 2

Concept:

The area of a 2D shape is the amount of space contained within its perimeter. It's expressed in square units like $cm^{2}$, $m^{2}$, and so on.

Given:

The area of the given square is $4x^{2} +12x+9$.

Find:

Find the side of the square.

Solution:

Area of the square $=side*side=side^{2}$.

The given area of the square = $4x^{2} +12x+9$

$side^{2} =4x^{2} +12x+9$

$side^{2} =4x^{2} +6x+6x+9$

$side^{2} =2x(2x+3)+3(2x+3)$

$side^{2} =(2x+3)(2x+3)$

$side^{2} =(2x+3)^{2}$

$side =(2x+3)$

Hence the side of the given square is $2x+3$ unit.