Question

a side of the sguare with area 9x*2+12x+4 sq.units is​

Answer 1

Step-by-step explanation:

Let the side of the square = x

Area of square = (s)²

Area we have = 9x²+12x+4

(s)² = 9x²+6x+4

(s)² = 9x²+6x+6x+4

(s)² = 3x(3x+2)+2(3x+2)

(s)² = (3x+2)(3x+2)

3x+2=0

x = -2/3

(s)² = ⅔

(s) = √⅔

Side of the square is √⅔ units.

Happy learning

Mark me as brainliest