A side of the square with area (4x^2+12x+9) square units is
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Given:
Area of square, a^2 = (4x^2 + 12x + 9) sq units
Where a = side of square
a^2 = 4x^2 + 12x + 9
a^2 = (2x)^2 + 2*2x*3 + 3^2
a^2 = (2x + 3)^2
a = (2x + 3) Units
There side of the square, a = (2x + 3) Units. ——> Answer
Area of square, a^2 = (4x^2 + 12x + 9) sq units
Where a = side of square
a^2 = 4x^2 + 12x + 9
a^2 = (2x)^2 + 2*2x*3 + 3^2
a^2 = (2x + 3)^2
a = (2x + 3) Units
There side of the square, a = (2x + 3) Units. ——> Answer
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