Question

A SIDECAR PROBLEM



Atkins, Baldwin, and Clarke had to go on a journey of fifty-two miles across country. Atkins had a motorcycle with a sidecar for one passenger. How was he to take one of his companions a certain distance, drop him on the road to walk the remainder of the way, and return to pick up the second friend, who, starting at the same time, was already walking on the road, so that they should all arrive at their destination at exactly the same time? The motorcycle could do twenty miles an hour, Baldwin could walk five miles an hour, and Clarke could walk four miles an hour. Of course, each went at his proper speed throughout and there was no waiting. I might have complicated the problem by giving more passengers, but I have purposely made it easy, and all the distances are an exact number of miles-without fractions. Let's see who comes up with an answer with a clear justification (Very importantly).

Answer 1

Answer:

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Explanation:

Atkins takes Clarke 40 miles in his car and leaves him to walk the remaining

12 miles. He then rides back and picks up Baldwin at a point 16 miles

from the start and takes him to their destination. All three arrive in exactly

5 hours. Or Atkins might take Baldwin 36 miles and return for Clarke, who

will have walked his 12 miles. The sidecar goes 100 miles in all, with no passenger for 24 miles.