A sign reads "arkansas". three letters are removed and put back into the three empty space at random. what is the probability the sign still reads "arkansas"?
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Let a,b,c be the 3 words taken out.
Now, the words can be put back in 3! ways.
This 3! becomes our sample space.
Out of these 3! ways, we can be sure that 1 of them is exactly 'abc'. 1 of them will give us our original word back.
Therefore P(word) becomes 1/3!= 1/6
Hope my answer helps.
Now, the words can be put back in 3! ways.
This 3! becomes our sample space.
Out of these 3! ways, we can be sure that 1 of them is exactly 'abc'. 1 of them will give us our original word back.
Therefore P(word) becomes 1/3!= 1/6
Hope my answer helps.
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