Question

a silicon chip used in an integrated circuit of a microcomputer has a mass of 5.68mg. how many silicon atoms are present in this chip?

Answer 1

(5.68 mg) x (1 g/1000 mg) x (1 mol Si/28.09 g) x (6.022x1023 atoms/1 mol) = 1.22 x 1020 Si atoms.......

Answer 2

The silicon chip has $1.22 \times 10^{20}$ silicon atoms.

• The silicon chip used in an integrated circuit of a microcomputer weighs 5.68mg.
• When weight is converted into grams, it gives $5.68 \times 10^{-3}$.
• To find the number of silicon atoms required, the weight must be divided with atomic weight as shown

• $\frac{5.68 \times 10^{-3}}{28}$
• The obtained value must be multiplied with $N_A$ value which is $6.023 \times 10^{23}$.
• This gives $1.22 \times 10^{20}$ as the numbers of silicon atoms present in the chip.

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