Question

a silicon diode of forward resistance 13 ohm is connected in series with an ac voltage of peak value 24 volt and a load resistance of 220 ohm.calculate the peak current and peak voltage across the load?

Answer 1

Hey there !

Solution:

Given Information:

• Forward Resistance = 13 Ω
• Load Resistance = 220 Ω
• Peak Value of Potential Difference = 24 V

To find:

• Peak Value of Current

Illustration:

Net Resistance = Forward Resistance + Load Resistance

=> Net Resistance = 220 Ω + 13 Ω = 233 Ω

=> Potential Difference = 24 V

Applying Ohm's Law,

V = IR

=> I = V / R

=> I = 24 V / 233 Ω

=> I = 0.103 A

Hence the peak current value is 0.103 A or 103 mA.

Hope my answer helped !