Physics, asked by limnamathew5080, 1 year ago

A Silicon PN junction at a temperature of 20
c C has a reverse saturation current
of 10 pico - Ameres (pA). The reserve saturation current at 40
cC for the same
bias is approximately
(A) 30 pA (B) 40 pA
(C) 50 pA (D) 60 pA

Answers

Answered by Maira9991
3

option ''b'' is correct

By increasing of temperature by 10°C, Io become double so by increasing temperature 20°C, Io become 4 time than initial value and it is 40 PA.

Answered by shivaprasadvangalasl
0

The accurate solution is alternative B) 40PA

For a 10°C boom in temperature, lo doubles, so for a 20°C boom in temperature, lo turns into 4 instances of the preliminary cost and it is forty PA.

  • In a PN junction diode, the opposite saturation present day is because of the diffusion waft of minority electrons from p-aspect to n-aspect and minority holes from n-aspect to p-aspect.
  • Therefore, the saturation opposite present-day relies upon the electron-hollow diffusion coefficient
  • The opposite saturation present day of the diode will increase with growing temperature. Nature of the opposite present-day of an excessive temperature-sensitive silicon diode.
  • The opposite saturation present day of the diode will increase with growing temperature.
  • The boom is 7%/°C for each germanium and silicon and more or less doubles for every 10°C booms in temperature.
  • The opposite saturation present day of a silicon diode is at the order of nano amperes (nA).

Hence

The accurate solution is alternative B) 40PA

#SPJ3

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