A silicon specimen is made into a p- type semiconductor by doping on an average one indium atom per 7
: 510
silicon atoms. if the number density of atoms in the silicon specimen is
28 3
510 atm/m then the no. of acceptor atoms in silicon per
cubic centimeter will be?
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The question looks messed up with the wrong numbers. I am giving an assumed answer based on a similar question from another website.
The Number density of the atoms in the silicon specimen = 5 x 10²⁸ atoms/m³.
When it is converted to cm³, it's value will become = 5 x 10²² atoms/cm³
No. of silicon atoms needed to dope 1 atom of indium = 5 x 10⁷ atoms.
Therefore, the total number of Indium atoms (n) doped per cm³ of the Silicon atoms = 5 x 10²² / 5 x 10⁷ = 1 x 10¹⁵atoms/cm³.
The Number density of the atoms in the silicon specimen = 5 x 10²⁸ atoms/m³.
When it is converted to cm³, it's value will become = 5 x 10²² atoms/cm³
No. of silicon atoms needed to dope 1 atom of indium = 5 x 10⁷ atoms.
Therefore, the total number of Indium atoms (n) doped per cm³ of the Silicon atoms = 5 x 10²² / 5 x 10⁷ = 1 x 10¹⁵atoms/cm³.
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