Question

A silver coin weighing 11.34 g was dissolved in nitric acid. When Sodium Chloride was added to the solution all the silver (present as AgNO3) was precipitated as silver chloride. The weight of the precipitated silver chloride was 14.35 g. Calculate the percentage of silver in the coin.​

Answer 1

NaCl + AgNO3 ----> AgCl + NaNO3

molar mass of AgCl is 143 g

weight of silver coin is 11.34 g

weight of silver chloride(AgCl) is 14.35 g

molar mass of Ag is 108 g

according to question, if 143g of AgCl is precipitated by 108 g of Ag

then 14.3 g of AgCl will be precipitated by 10.8 g of Ag .

So the percentage of presence of Ag in silver coin is

(10.8/11.34)100

= 95.23 %

Hence 95.23% of Ag is present in silver coin.

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