Question

A silver cylindrical rod has a length of 0.5m and a radius of 0.4m, find the density of the rod
if its mass is 2640kg

Answer 1

Answer:

mass=2640

height=0.5

radius=0.4

volume=pie r^2h

=22/7×(0.4)^2×0.5

=0.25m^3

density =mass/volume

=2640÷0.25

=10560kg/m^3

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