Question

A silver ornament of mass "m" is polished with gold to 1% of the mass of silver.Compute the ratio of the number of atoms of gold and silver in ornament.{ Molar mass of gold=197g/mol, silver=108 g/mol} tell fast plzz 20 points

Answer 1

Answer:

$ratio = \frac{atom \: of \: gold}{atom \: of \: silver}$

Explanation:

atom of silver= m/108×6.022×10^23

atom of gold=(0.01m)/197×6.022×10^23

we get the answer = 108:19700

=27:4924