Question

A silver sample contain 90% of Silver and the rest Mercury.How many atoms of silver are present in 1 gram of this sample of Silver?

Please solve with accurate steps!!

Answer 1

$\huge\red{As-Salamu-Alykum}$

_____________

$\huge\pink{Given }$

In sample 90% silver means that mass of silver is 0.9g and 0.1 g is mercury

So.......

Mass of Ag = 0.9g

Molar mass of Ag = 107g/mol

$\huge\blue{Required:-}$

Atoms of silver =?

$\huge\orange{Solution:-}$

Moles of Ag = mass / molar mass

Moles of Ag = 0.9/107

Moles of Ag = 0.0084mol

Now ......

Moles of Ag = number of atoms of Ag / Avagadro number

Number of atoms of silver = moles of Ag × Avagadro number

Number of atoms of Ag = 0.0084 × 6.023 ×10^23

Number of atoms of Ag = 0.05 ×10^23

Number of atoms of Ag = 5 ×10^21

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$\huge\red{INSHALLAH it will help U}$

Answer 2

Hey !!

(Ag) = 0.9 g

Now, Molar mass = 107  g/mol

We know that, Moles of Ag = Mass / Molar mass

Now, 0.9 / 107

= 0.0084 mol

Moles of atom of Ag = Moles of Ag * Avagadro number

NOTE :- Avagadro value is ''6.023 * 10²³

Ag = 0.0084 * 6.023 * 10²³

           = 0.05 * 10²³

           = 5 * 10²¹

Hope it helps you !!