A SILVER WIRE HAS A DIAMETER 0.4mm AND RESISTIVITY 1.6x10^-8 ohm-m.HOW MUCH LENGTH OF THIS WIRE IS REQUIRED TO MAKE A 1 OHM COIL?
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Cross sectional area of the wire = 3.14 x (radius)2 = 3.14 x 0.04 x 10^-6 m^2
Therefore, A = 1.26 x 10^-6 m^2 Length of the wire = resistance x resistivity/ area = 1 x (1.26 x 10-6/1.6 x 10-8) m = 1260/16 = 78.75 m.
Therefore, the length of the wire is 78.75 m.
Therefore, A = 1.26 x 10^-6 m^2 Length of the wire = resistance x resistivity/ area = 1 x (1.26 x 10-6/1.6 x 10-8) m = 1260/16 = 78.75 m.
Therefore, the length of the wire is 78.75 m.
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