a silver wire has a resistance of 2.7 ohm at 100°C. Determine the temperature coefficient of resistivity of silver.?
Answers
Answered by
0
Answer:
A silver wire has a resistance of 2.1 Ω at 27.5 ° C, and a resistance of 2.7 Ω at 100 °C. Determine the temperature coefficient of resistivity of ...
Answered by
0
ANSWER :
T
T 1
T 1
T 1 =27.5
T 1 =27.5 o
T 1 =27.5 o C,R
T 1 =27.5 o C,R 1
T 1 =27.5 o C,R 1
T 1 =27.5 o C,R 1 =2.1Ω,T
T 1 =27.5 o C,R 1 =2.1Ω,T 2
T 1 =27.5 o C,R 1 =2.1Ω,T 2
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7Ω
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:α=
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:α= R
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:α= R 1
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:α= R 1
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:α= R 1 (T
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:α= R 1 (T 2
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:α= R 1 (T 2
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:α= R 1 (T 2 −T2)
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:α= R 1 (T 2 −T2)R
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:α= R 1 (T 2 −T2)R 2
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:α= R 1 (T 2 −T2)R 2
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:α= R 1 (T 2 −T2)R 2 −R
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:α= R 1 (T 2 −T2)R 2 −R 1
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:α= R 1 (T 2 −T2)R 2 −R 1
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:α= R 1 (T 2 −T2)R 2 −R 1
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:α= R 1 (T 2 −T2)R 2 −R 1
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:α= R 1 (T 2 −T2)R 2 −R 1 =0.0039
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:α= R 1 (T 2 −T2)R 2 −R 1 =0.0039 o
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:α= R 1 (T 2 −T2)R 2 −R 1 =0.0039 o C
T 1 =27.5 o C,R 1 =2.1Ω,T 2 =100 o C,R 1 =2.7ΩTemperature coefficient of resistivity is:α= R 1 (T 2 −T2)R 2 −R 1 =0.0039 o C −1
Similar questions