a silver wire has diameter of 0.4mm & resistivity=1.6×10^-8ohm-m. how much length of this wire is required to make a 1ohm coil
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R = ρL/A
L = RA / ρ
= 1 * (π * (0.4/2 * 10^-3)^2) / (1.6 * 10^-8)
= 7.8 m
Length of wire required is 7.8 m
L = RA / ρ
= 1 * (π * (0.4/2 * 10^-3)^2) / (1.6 * 10^-8)
= 7.8 m
Length of wire required is 7.8 m
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hope it helps , from horus22
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