Question

A silver wire has resistance of 2.1Q at 27.5 °C. If temperature coefficient of silver is · 3.94 x 10-3 tc, find the silver wire resistance at 100°C​

Answer 1

Answer:

Given, T_0=27.5^{\circ}C,R_0=2.1 ohm, T=100^{\circ}C,and, R=2.7ohm

using the relation , R=R_0[1+\alpha(T-T_0)], where \alpha is the coefficient of resistance .

so,\alpha=\frac{R-R_0}{R_0(T-T_0)}\\\\=\frac{2.7-2.1}{2.1(100-27.5)}\\\\=\frac{0.6}{152.25}\\\\=3.94\times10^{-3}/^{\circ}C

hence, coefficient of resistance of silver is 3.94 × 10^-3 / °C