a silver wire of radius 0.1m carries a current of 2A .if charge density in silver is 5.86 then drift velocity is
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Explanation:
1 hour 15 minutes=4500 seconds
i=q/t
i=90/4500=0.02 amperes
j=i/a
j=0.02/(3.14*0.05*0.05)
j=2.55*10^4 amp/m^2
drift velocity=j/ne
v(d)=2.55*10000/((5.28*10^22)*(1.6*10^-19)
v(d)=2.69*10^-7
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