A silver wire when bent in the form of a square encloses an area of 484 sq. cm. If the same wire is bent in the form of a circle, Find the area of the circle
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29
area of square=side×side
√484=side=22cm.
perimeter of square=length of wire
4×22=88cm.
circumference of circle=length of wire
88=2×22/7×r
88×7/22×2=r=14cm
area of circle=π×r×r=22/7×14/1×14/1=616sq. cm
ans.-616sq. cm.
√484=side=22cm.
perimeter of square=length of wire
4×22=88cm.
circumference of circle=length of wire
88=2×22/7×r
88×7/22×2=r=14cm
area of circle=π×r×r=22/7×14/1×14/1=616sq. cm
ans.-616sq. cm.
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15
Answer:
Area of the circle = 616 cm²
Step-by-step explanation:
Area of the square is given to be 484 square centimeter
Now, the area of the square is given by the formula : side²
⇒ Side² = 484
⇒ Side of the square = √484
⇒ Side of the square = 22 cm
Now, Length of the wire = Perimeter of square
⇒ Length of wire = 4 × side
⇒ Length of wire = 4 × 22
⇒ Length of wire = 88 cm
Also, Circumference of the circle = Length of wire
⇒ 2π × radius = 88
⇒ radius = 14 cm
Area of the circle = π·radius²
⇒ Area of the circle = 616 cm²
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