a sim of money invested at compound interest amounts to 16500 in 1 year and to 19965 in 3 years find the rate percent and the original sum of money
Answers
Answered by
11
Amount1 = 16500
Amount3= 19965.
Formula-
Amount1=P(1+r/100)^n.
n=no. of years
16500=P(1+r/100)^1
19965=P(1+r/100)^3
On diving them,
19965/16500=P(1+r/100)^3 / P(1+r/100)^1
[P gets canceled]
19965/16500= (1+r/100)^2
121/100=(1+r/100)^2
11/10= 1 + r/100
11-10/10 = r/100
1/10 x 100 = r
R= 10%
Therefore, original sum = 15000
Amount3= 19965.
Formula-
Amount1=P(1+r/100)^n.
n=no. of years
16500=P(1+r/100)^1
19965=P(1+r/100)^3
On diving them,
19965/16500=P(1+r/100)^3 / P(1+r/100)^1
[P gets canceled]
19965/16500= (1+r/100)^2
121/100=(1+r/100)^2
11/10= 1 + r/100
11-10/10 = r/100
1/10 x 100 = r
R= 10%
Therefore, original sum = 15000
Answered by
0
Answer:
15000
Step-by-step explanation:
Amount1 = 16500
Amount3= 19965.
Formula-
Amount1=P(1+r/100)^n.
n=no. of years
16500=P(1+r/100)^1
19965=P(1+r/100)^3
On diving them,
19965/16500=P(1+r/100)^3 / P(1+r/100)^1
[P gets canceled]
19965/16500= (1+r/100)^2
121/100=(1+r/100)^2
11/10= 1 + r/100
11-10/10 = r/100
1/10 x 100 = r
R= 10%
Therefore, original sum = 15000
Similar questions