A simple closed cycle gas turbine plant receives air at 1 bar and
15°C, and compresses it to 5 bar and then heats it to 800°C in the
heating chamber. The hot air expands in a turbine back to 1 bar.
Calculate the power developed per kg of air supplied per second.
Take CP for the air as 1 kJ/kg K.
Answers
Answer:
Step-by-step explanation:
W1 = RTln(P1/P2) = 8.314*(273+15)*ln(1/5) = -3853.69 J (isothermic)
W2 = PdV = nRdT = 8.314*((800+273) - (15+273)) = 6526.49 J (isobaric)
W3 = RTln(P1/P2) = 8.314*(273+800)*ln(5/1) = 14357.67 J (isothermic)
W = W1 + W2 + W3 = 17030.47 J
To calculate power we need time, here it is not given. Also, Cp is not really necessary here.
Answer:
Power developed will be 13.85 kW
Step-by-step explanation:
Given mass (air) m1 = 0.1 kg/s
Pressure P1 = 0.1 MN/m^2
Pressure P2 = 0.4 MN /m^2
T4 = 285 K
So Cp = 1.0KJ/Kg K
For air γ = 1.4
So we need to find temperature at turbine inlet T3
T3 / T4 = (P2 / P1) ^γ – 1 / γ
T3 / 285 = (0.4 / 0.1)^1.4 – 1 / 1.4
= 4^2/7 x 285
= 1.485 x 285
= 423.49
= 423.5 K
Now power developed will be
P = m a Cp (T3 – T4)
= 0.1 x 1.0 (423.5 – 285)
= 0.1 x 138.5
P = 13.85 kW
Reference link will be
https://brainly.com/question/12937453