Question

a simple cubic unit cell of a metal has an edge length 6.34 Armstrong the radius of the atom will be???​

Answer 1

Answer:

a=rxx2sqrt2=2sqrt2xx1.28xx10^(-8)cm

Answer 2

Given:

A simple cubic unit cell

Edge length = 6.34 A°

To Find:

The radius of the atom

Solution:

A simple cubic unit cell is a type of primitive unit cell. It can be visualized as a cube with 1 atom at each corner.

Each atom contributes 1/8th to the unit cell.

We know that a cube has 8 corners

Thus the net atom/s = $8 X \frac{1}{8}$ = 1 atom

The relation between the edge length a and the radius of the atom r in a simple cubic unit cell is:

a = 2r

Substituting the value of a,

r = 6.34A° / 2

= 3.17A°

We know that 1 A° = 10⁻¹⁰m

⇒ 3.17A° = 3.17 X 10⁻¹⁰m

Hence, the radius of the atom is 3.17 X 10⁻¹⁰m.