Question

a simple electric circuit as a 24 volt battery and a resistor of 60 ohms what will be the current in a circuit​

Answer 1

Answer:

Explanation:

I=V/R

I=24/60

=2/5

=0.4A

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Current\:flow=0.4\:A}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given: }} \\ \tt: \implies Volt(V) = 24 \: V \\ \\ \tt: \implies Resistance(R) = 60 \: \Omega \\ \\ \red{\underline \bold{To \: Find: }} \\ \tt: \implies Current \: (I) = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies V = IR \\ \\ \tt: \implies 24 = I \times 60 \\ \\ \tt: \implies \frac{24}{60} = I \\ \\ \tt: \implies 0.4 = I \\ \\ \green{\tt: \implies I= 0.4 \: A}\\ \\ \green{\tt \therefore Current\:flow\: in \: the \: circuit \: is \: 0.4 \: A} \\ \\ \blue{\bold{Some \: related \: concept : }} \\ \\ \red{\tt{For \: series \: combination \: resistance}} \\ \orange{\tt \circ \: R_{effective} = R_{1} + R_{2} + R_{3} + ....... + R_{n}} \\ \\ \red{\tt{For \: parallel \: combination \: resistance}} \\ \orange{\tt \circ \: R_{effective} = \frac{1}{ R_{1} } + \frac{1}{ R_{2} } + \frac{1}{ R_{3} } + ....... + \frac{1}{ R_{n} } }$