A simple harmonic motion had an amplitude A and time period T. Find the time required by it to travel directly from. (a)x=A to x=A/2. (b)x= -A/√2 to x=A/√2
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1)T/6
Second one I have doubt I think it is T/4
Second one I have doubt I think it is T/4
sahil102:
right how does you calculate it?????
Are u preparing for entrance examination?
First one we can calculate using x=Acos(wt) as we have to assume it starts from extreme position. Second one also apply the same logic.
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okkkk got it thank u so much
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okkkkkk
Answered by
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the answer is -
b)x= -A/root 2 to x = A /root 2
b)x= -A/root 2 to x = A /root 2
its a question........ we can get the answer by using eqution
equation
x=Asin(wt+phi)
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