A Simple Harmonic Motion is represented by d^2x/dt^2 +ax=0,what is its time period?
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DarkTitan4:
I didn't get it please explain more briefly
d²x/dt²= –ax
comparing it with , d²x/dt²= –w²x we get w²=a , i.e. w=√a
and T=2π/w = 2π/√a
comparing it with , d²x/dt²= –w²x we get w²=a , i.e. w=√a
and T=2π/w = 2π/√a
done
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