A simple harmonic motion of acceleration a and displacement x is represented by : a+(4π^2)x = 0
What is the time period of S.H.M?
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Answer:T= 2π√l/g
Explanation:
mg theeta = -kx
mg x/l = -kx
k = mg/l
T = 2π√m/k
=2π√m/mg × l
T =2π√l/g
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