Question

A simple harmonic oscillator has a period of 0.01 s and an amplitude of 0.2 m. The magnitude of the
velocity in m sec at the centre of oscillation is​

Answer 1

Solution :

⏭ Given:

✏ Time period of oscillation = 0.01s

✏ Amplitude = 0.2m

⏭ To Find:

✏ Magnitude of velocity in mps at the mean position

⏭ Concept:

✏ We know that velocity of oscillator is maximum at mean position and minimum (= 0) at extreme point.

⏭ Formula:

✏ Formula of maximum velocity in oscillatory motion is given by

• Vmax = Aω = A × 2π/T

⏭ Terms indication:

✏ A denotes amplitude

✏ ω denotes angular velocity

✏ T denotes time period

⏭ Calculation:

✏ Vmax = 0.2 × 2π / 0.01

✏ Vmax = 125.6 mps