Physics, asked by Saurabh2179, 3 months ago

a simple harmonic oscillator of mass 0.03 kg is attached to a spring of force constant 90 N/m.The mass is parallel to a distance of 0.009 m and relesed to execute simple harmoni motion.calculate the time period of motion

Answers

Answered by Anonymous
0

Answer:

Explanation:

Ultrasound machines are used by medical professionals to make images for examining internal organs of the body. An ultrasound machine emits high-frequency sound waves, which reflect off the organs, and a computer receives the waves, using them to create a picture. We can use the formulas presented in this module to determine the frequency, based on what we know about oscillations. Consider a medical imaging device that produces ultrasound by oscillating with a period of  

0.400

μ

s

. What is the frequency of this oscillation?

Strategy

The period (T) is given and we are asked to find frequency (f).

Solution

Substitute  

0.400

μ

s

for T in  

f

=

1

T

:

f

=

1

T

=

1

0.400

×

10

6

s

.

Solve to find

f

=

2.50

×

10

6

Hz

.

Significance

This frequency of sound is much higher than the highest frequency that humans can hear (the range of human hearing is 20 Hz to 20,000 Hz); therefore, it is called ultrasound. Appropriate oscillations at this frequency generate ultrasound used for noninvasive medical diagnoses, such as observations of a fetus in the womb.

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