Question

A simple microscope is rated 5 X for a normal relaxed eye. What will be its magnifying power for a relaxed farsighted eye whose near point is 40 cm?

Answer 1

Given :

Magnification for a normal relaxed eye, m = 5

Least distant of distinct vision, D = 25 cm

Now,

Let the focal length be f.

The image will form at infinity, as the eye is relaxed.

The magnifying power =m= D/f

5=25/f

⇒f=5 cm

For the relaxed far-sighted eye, D = 40 cm.

Magnification  m=D/f

=40/5

=8

The magnifying power for a simple microscope is 8X.

Answer 2

Hey !

Refer the attachment !!

Thanks!