Physics, asked by kiran45801, 12 hours ago

A simple model for conduction particles in a metal predicts that σ = (e2nl)/(2mu) where σ is the conductivity, n is the density of particles, u is the typical velocity of random motion of the particle, m is the particle mass and l is the typical distance the particle travels between collisions. Assume here that the particles are Bosons instead of electrons (Fermions). Obtain an expression for σ, in terms of the particle mass and the gas volume and eliminating u, if the particles are described by an ideal Boson gas at zero temperature. 1) Describe how you would proceed (making reference to the textbook) to obtain the result. 2) In which case, Boson or Fermion, would you expect the conductivity to be greater, all other things being equal? Explain. Check your spelling or try different keywords.

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Answered by AvantikRaj
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A simple model for conduction particles in a metal predicts that σ = (e2nl)/(2mu) where σ is the conductivity, n is the density of particles, u is the typical velocity of random motion of the particle, m is the particle mass and l is the typical distance the particle travels between collisions. Assume here that the particles are Bosons instead of electrons (Fermions). Obtain an expression for σ, in terms of the particle mass and the gas volume and eliminating u, if the particles are described by an ideal Boson gas at zero temperature. 1) Describe how you would proceed (making reference to the textbook) to obtain the result.

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