Question

A simple pendulam has a time period of 4s for a length of 1 m. Calculate the value of acceleration due to gravity ?​

Answer 1

Answer:

for the question -

A simple pendulum has a time period of 4 sec on the surface of earth. Its time period on the surface of moon is ??

Answer 2

Given :

• Time period of the simple pendulam (T) = 4s.
• Length of the pendulum(l) = 1m

To Find :

• Acceleration due to gravity.

Basic Concepts :

Length of pendulum : The length of the Simple pendulum (L) is he length of the thread between the point of suspension and centre of the bob.

Time Period : The time taken by the pendulum to complete one oscillation is called Time period (T).

Formula Applied :

$\underline{\boxed{\sf gravity = 4 \pi^2 \dfrac{l}{T^2}}}$

• l = length of pendulum.
• T = Time period.

Solution :

${\longrightarrow \sf gravity = 4 \pi^2 \dfrac{l}{T^2}}\\\\{\longrightarrow \sf g = 4 \times \dfrac{22}{7} \times \dfrac{22}{7} \times \dfrac{1}{4}}\\\\{\longrightarrow \sf g = 4 \times 3.14 \times 3.14 \times 0.25}\\\\{\longrightarrow \sf g = (3.14)^2 \times 1}\\\\{\longrightarrow \sf g = 9.8586\: ms^{-2}}\\\\{\longrightarrow \sf g = 9.86 \:ms^{-2}}$

Required Answer :

Value of acceleration due to gravity is $\underline{\sf 9.86\: ms^{-2}}$