Question

A simple pendulum 4m long swings with amplitude of 0.2m. Find velocity of pendulum at lowest point and its acceleration at extreme ends.

Answer 1

Answer:

Explanation:

Answer:-

L = Length of pendulum = 4m

Amplitude (r)  = 0.2 m

Time period of simple pendulum is given by = 2 √(l/g) = 2 √4/10 = 3.97 sec (Taking g = 10 here).

i) Velocity of the pendulum at its lowest point

V = Ψ √(r² - y²) .... (1)

At lowest point, y= 0

r = 0.2 , Ψ = 2/T = 2/3.97

Substituting above in (1) we get,

V = 0.32 m/s

ii) Acceleration at extreme ends

a = Ψ² y ...(2)

Here y = 0.2,   Ψ = 2/T = 2/3.97

Substituting above in (2) we get,

a = 0.5 m/s²

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