Question

A simple pendulum 50 oscillations in 22.3s. find it frequency?

Answer 1

Answer:

2.2

Explanation:

50/22.3

2.2Hz

Answer 2

Answer:

Required frequency is 2.242 HZ

Explanation:

Given, a simple pendulum 50 oscillations in 22.3 s.

Now,by Unitary method, the simple pendulum complete 1 oscillation in

$\frac{22.3}{50} \: sec = 0.446 \: sec$

So,time period of the pendulum 0.446 sec.

We know,

$f = \frac{1}{t}$

Where f is frequency of pendulum and t is time period.

So, required frequency,f $= \frac{1}{0.446} = 2.242 \:HZ$

Extra information about pendulum:

A pendulum is a weight that is hung from a swing tent so that it can swing freely.[1] When the pendulum is moved sideways from its equilibrium position, it is acted upon by a restoring force due to gravity, which accelerates it back toward its equilibrium position. When released, the restoring force on the mass of the pendulum causes the pendulum to oscillate around the equilibrium position, swinging back and forth. The time taken for one complete cycle - a left and a right turn - is called a period. The period depends on the length of the pendulum and to a lesser extent on the amplitude and width of the pendulum stroke.

Oscillation related two more questions:

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