Physics, asked by Ritasha, 1 year ago

a simple pendulum complete 40 oscillations in 1 minutes find its frequency &timeperiod

Answers

Answered by tnwramit1
27
Given
Oscillations =40
Time=1 min

Frequency =  \frac{number of oscillations}{total \: time}

f =  \frac{40}{60}  = 0.66667hz

Time period =  \frac{1}{f}

t =  \frac{1}{0.6667}
T=1.5 seconds

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tnwramit1: np and tnx for brainliest
Answered by itzshivam15
1

Answer:

Given

Number of Oscillations, N=40

Time t=1min

Frequency f= N/t = 40/60 =0.667Hz

Time period,T= 1/f =1.5sec

Hence, frequency is 0.667Hz and time period is 1.5sec

Explanation:

hope it helps you

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