Question

a simple pendulum complete 72 number of oscillation in 9 seconds calculate its time period and frequency​

Answer 1

Answer:

Frequency: 8 oscillations

Time period: 1/8 sec

Explanation:

As frequency= oscillations/sec

So, 72/9=8

Time Period= 1/Frequency

So, 1/8 sec

Answer 2

Given,

72 number of oscillation in 9 seconds

To Find,

Calculate the time period and frequency of this simple pendulum.

Solution,

This is a numerical problem and can be solved by the following procedures,

The time period of the simple pendulum is equal to the time taken for completing one oscillation, i. e.,

The Time Period(x)= Total Time taken (T)/ Number of oscillation (n)

Now,

Total Time taken (T) = 9 Seconds

Number of Oscillations (n) = 72

Time period (x)= ?

Time taken for One oscillation will be T/n,

i.e.,

       9/72= 0.125 seconds

Now, let's calclate the frequency of this simple pendulum.

Frequency (F)= Number of Oscillations (n) per second.

Therefore, F= 1/(x)

Time period (x)= 0.125 seconds

Therefore,

            F= 1/ 0.125= 8 Hz

(To remember:

    1. Time period = (Total time taken)/ (Number of Oscillation)

         i.e.,          $x= T/n$

    2. Frequency =                                  

                                  $1\\-\\x$   )

Here, the Time Period is 0.125 seconds and the Frequency is 8 Hz.