A simple pendulum completee 40oscillations in on minute find it's frequency and it's time periods
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frequency is the no. of oscillations per one second. so, for 60sec, it undergoes 40 oscillations. then for one second, it undergoes 40/60=0.6 oscillations.so,it's frequency is 0.6Hz.
it's time period is 2π√l/g.
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