Question

A simple pendulum completes 300 oscillations in 120 seconds. Calculate its frequency and time period.

Answer 1

Explanation:

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Answer 2

Answer:

A simple pendulum completes 300 oscillations in 120 seconds, Its

Frequency   = 2.5Hz

Time period = $0.4s$

Explanation:

• The number of oscillations completed per time is the frequency of oscillation. It can be obtained by the equation,  

        $Frequency = \frac{No\ of\ oscillations}{time\ taken}$

• The time period of an oscillation can be expressed as,

        $Time\ period = \frac{1}{frequency}$

• Let f be the frequency of oscillation, N be the number of oscillations completed in time t and T be the time period.

         So as per definition,

        $f = \frac{N}{t}$                            ...(1)

         and

        $T = \frac{1}{f}$

• In the question, it is given that,

        N   $=300$

         t   $=120s$

• Then using equation(1),

         f = $\frac{300}{120} =2.5 Hz$

         T = $\frac{1}{2.5}= 0.4s$