Question

a simple pendulum completes 360 oscillations in 2 minutes . Calculate its frequency and time period

Answer 1

Answer:

The frequency and time period of the simple pendulum is 3.5 Hz and 0.28 seconds. Explanation: Given that, Number of oscillations is 420 in 2 minutes or 120 seconds.

Answer 2

Answer:

Time Period (T): 0.33 seconds

Frequency (F): 3 Hz

Explanation:

The total time taken for a pendulum to complete one oscillation is called time period (T).

The pendulum makes 360 oscillations in 2 minutes. We have to find out the time taken to complete one oscillation.

Step 1: Convert minutes into seconds.

1 minute = 60 seconds

2 minutes = $x$ seconds

120 seconds are there in 2 minutes.

Step 2: Find the time taken for one complete oscillation.

360 osc → 120 sec

1 osc → $x$ sec

$120 = 360 \times x$

$\frac{120}{360} = x$

$0.33 = x$

0.33 seconds are required to complete one oscillation.

The frequency could be defined as the number of oscillations occurring in one second.

To calculate the frequency of its oscillation, we have to the number of oscillations in one second.

1 sec → $\frac{360}{120}$ = $3s^{-1}$ or 3Hz is the frequency.