Question

A simple pendulum completes 3600 oscillations in half an hour find its frequency

Answer 1

$\huge{\underline{\tt{\red{Answer-}}}}$

2Hz

$\huge{\underline{\tt{\blue{Explanation-}}}}$

Formula of Frequency = $f= \dfrac{N}{T}$

where N = Number of Oscillations, N= 3600

T = time in second = $\dfrac{1}{2} hour = 1800 \ sec$

$\implies \dfrac{N}{T} = \dfrac {3600}{1800}= 2 Hz$

Answer 2

\huge{\underline{\tt{\red{Answer-}}}}

Answer−

2Hz

\huge{\underline{\tt{\blue{Explanation-}}}}

Explanation−

Formula of Frequency = f= \dfrac{N}{T}f=

T

N

where N = Number of Oscillations, N= 3600

T = time in second = \dfrac{1}{2} hour = 1800 \ sec

2

1

hour=1800 sec

\implies \dfrac{N}{T} = \dfrac {3600}{1800}= 2 Hz⟹

T

N

=

1800

3600

=2Hz