Question

A simple pendulum completes 40 oscillations in one minute. Find it's frequency and time period.

Answer 1

1 min =60sec

Frequency= No of Oscillations/Time Taken

=40/60

=0.667 hertz

Time period=Time taken /No of Oscillations

=60/40

=1.5 sec

Answer 2

Explanation:--

Given that ,

Number of Oscillations, Number of oscillation N=40

Time taken t=1min

Frequency f= N/t

=0.667Hz

Time period,T= 1/frequency

=1.5sec

Hence, frequency is 0.667Hz and time period is 1.5sec