a simple pendulum completes 40 seconds in one minute find its first frequency and second time period
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1) Frequency
=no of oscillations per second
=40 oscillation / 60sec
=0.6667 Hz
2)Time period
=1/frequency
=time taken for 1 oscillation
=time taken / No of oscillation
= 60/40
= 1.5 sec^⁻¹
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1) Frequency
=no of oscillations per second
=40 oscillation / 60sec
=0.6667 Hz
2)Time period
=1/frequency
=time taken for 1 oscillation
=time taken / No of oscillation
= 60/40
= 1.5 sec^⁻¹
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(1) Frequency = oscillation/Time
Frequency = 40/60
Frequency = 2/3Hz
Frequency = 0.67 Hz
(2) Time period = Time/Oscillation
Time Period = 60/40
Time Period = 3/2sec
Time Period = 1.5sec
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